Base | Representation |
---|---|
bin | 100100110100101111110… |
… | …000100111111101111111 |
3 | 22221220202110211120002111 |
4 | 210310233300213331333 |
5 | 312430014433404434 |
6 | 5214302422234451 |
7 | 350553031465243 |
oct | 44645760477577 |
9 | 8856673746074 |
10 | 2530537013119 |
11 | 89621619a205 |
12 | 34a527885a27 |
13 | 1548230bb47b |
14 | 8a69b58a423 |
15 | 45c59964964 |
hex | 24d2fc27f7f |
2530537013119 has 2 divisors, whose sum is σ = 2530537013120. Its totient is φ = 2530537013118.
The previous prime is 2530537013113. The next prime is 2530537013149. The reversal of 2530537013119 is 9113107350352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2530537013119 - 221 = 2530534915967 is a prime.
It is a super-2 number, since 2×25305370131192 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2530537013113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265268506559 + 1265268506560.
It is an arithmetic number, because the mean of its divisors is an integer number (1265268506560).
Almost surely, 22530537013119 is an apocalyptic number.
2530537013119 is a deficient number, since it is larger than the sum of its proper divisors (1).
2530537013119 is an equidigital number, since it uses as much as digits as its factorization.
2530537013119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 85050, while the sum is 40.
The spelling of 2530537013119 in words is "two trillion, five hundred thirty billion, five hundred thirty-seven million, thirteen thousand, one hundred nineteen".
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