Base | Representation |
---|---|
bin | 100100110100110100010… |
… | …110111011101101010111 |
3 | 22221220221212000020122001 |
4 | 210310310112323231113 |
5 | 312430144211224221 |
6 | 5214314220020131 |
7 | 350554656324652 |
oct | 44646426735527 |
9 | 8856855006561 |
10 | 2530614164311 |
11 | 8962557a5022 |
12 | 34a549691647 |
13 | 154836091c6c |
14 | 8a6a7910899 |
15 | 45c61604391 |
hex | 24d345bbb57 |
2530614164311 has 2 divisors, whose sum is σ = 2530614164312. Its totient is φ = 2530614164310.
The previous prime is 2530614164261. The next prime is 2530614164381. The reversal of 2530614164311 is 1134614160352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2530614164311 - 217 = 2530614033239 is a prime.
It is a super-2 number, since 2×25306141643112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2530614164381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265307082155 + 1265307082156.
It is an arithmetic number, because the mean of its divisors is an integer number (1265307082156).
Almost surely, 22530614164311 is an apocalyptic number.
2530614164311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2530614164311 is an equidigital number, since it uses as much as digits as its factorization.
2530614164311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 2530614164311 in words is "two trillion, five hundred thirty billion, six hundred fourteen million, one hundred sixty-four thousand, three hundred eleven".
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