2531137120843 has 2 divisors, whose sum is σ = 2531137120844. Its totient is φ = 2531137120842.

The previous prime is 2531137120717. The next prime is 2531137120879. The reversal of 2531137120843 is 3480217311352.

It is a happy number.

2531137120843 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2531137120843 - 2²¹ = 2531135023691 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2531137120796 and 2531137120805.

It is not a weakly prime, because it can be changed into another prime (2531137160843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265568560421 + 1265568560422.

It is an arithmetic number, because the mean of its divisors is an integer number (1265568560422).

Almost surely, 2^{2531137120843} is an apocalyptic number.

2531137120843 is a deficient number, since it is larger than the sum of its proper divisors (1).

2531137120843 is an equidigital number, since it uses as much as digits as its factorization.

2531137120843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 2531137120843 in words is "two trillion, five hundred thirty-one billion, one hundred thirty-seven million, one hundred twenty thousand, eight hundred forty-three".