Base | Representation |
---|---|
bin | 111001100011010010111110… |
… | …110101101100000110110000 |
3 | 1020012012111000210122222000222 |
4 | 321203102332311230012300 |
5 | 231134010402343330300 |
6 | 2254155022002032212 |
7 | 104212620122666531 |
oct | 7143227665540660 |
9 | 1205174023588028 |
10 | 253114214433200 |
11 | 7371715441226a |
12 | 2447b292348668 |
13 | ab3074cb9bcb3 |
14 | 4670b16d1a688 |
15 | 1e3e13551b785 |
hex | e634bed6c1b0 |
253114214433200 has 60 divisors (see below), whose sum is σ = 622938775830168. Its totient is φ = 98776278796800.
The previous prime is 253114214433193. The next prime is 253114214433211. The reversal of 253114214433200 is 2334412411352.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7716880382 + ... + 7716913181.
Almost surely, 2253114214433200 is an apocalyptic number.
253114214433200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
253114214433200 is an abundant number, since it is smaller than the sum of its proper divisors (369824561396968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
253114214433200 is a wasteful number, since it uses less digits than its factorization.
253114214433200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15433793622 (or 15433793611 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 253114214433200 its reverse (2334412411352), we get a palindrome (255448626844552).
The spelling of 253114214433200 in words is "two hundred fifty-three trillion, one hundred fourteen billion, two hundred fourteen million, four hundred thirty-three thousand, two hundred".
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