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2531414131 is a prime number
BaseRepresentation
bin1001011011100010…
…0101000001110011
320112102022011100221
42112320211001303
520141020223011
61055104553511
7116505444061
oct22670450163
96472264327
102531414131
111089a0a9a4
125a7922897
133145aacac
141a02ab031
15ec383971
hex96e25073

2531414131 has 2 divisors, whose sum is σ = 2531414132. Its totient is φ = 2531414130.

The previous prime is 2531414117. The next prime is 2531414153. The reversal of 2531414131 is 1314141352.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2531414131 - 27 = 2531414003 is a prime.

It is a super-2 number, since 2×25314141312 = 12816115005252970322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2531414096 and 2531414105.

It is not a weakly prime, because it can be changed into another prime (2531414161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265707065 + 1265707066.

It is an arithmetic number, because the mean of its divisors is an integer number (1265707066).

Almost surely, 22531414131 is an apocalyptic number.

2531414131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2531414131 is an equidigital number, since it uses as much as digits as its factorization.

2531414131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 25.

The square root of 2531414131 is about 50313.1606142965. The cubic root of 2531414131 is about 1362.8699003647.

Adding to 2531414131 its reverse (1314141352), we get a palindrome (3845555483).

The spelling of 2531414131 in words is "two billion, five hundred thirty-one million, four hundred fourteen thousand, one hundred thirty-one".