Base | Representation |
---|---|
bin | 1001011011100010… |
… | …0101000001110011 |
3 | 20112102022011100221 |
4 | 2112320211001303 |
5 | 20141020223011 |
6 | 1055104553511 |
7 | 116505444061 |
oct | 22670450163 |
9 | 6472264327 |
10 | 2531414131 |
11 | 1089a0a9a4 |
12 | 5a7922897 |
13 | 3145aacac |
14 | 1a02ab031 |
15 | ec383971 |
hex | 96e25073 |
2531414131 has 2 divisors, whose sum is σ = 2531414132. Its totient is φ = 2531414130.
The previous prime is 2531414117. The next prime is 2531414153. The reversal of 2531414131 is 1314141352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2531414131 - 27 = 2531414003 is a prime.
It is a super-2 number, since 2×25314141312 = 12816115005252970322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2531414096 and 2531414105.
It is not a weakly prime, because it can be changed into another prime (2531414161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265707065 + 1265707066.
It is an arithmetic number, because the mean of its divisors is an integer number (1265707066).
Almost surely, 22531414131 is an apocalyptic number.
2531414131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2531414131 is an equidigital number, since it uses as much as digits as its factorization.
2531414131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 25.
The square root of 2531414131 is about 50313.1606142965. The cubic root of 2531414131 is about 1362.8699003647.
Adding to 2531414131 its reverse (1314141352), we get a palindrome (3845555483).
The spelling of 2531414131 in words is "two billion, five hundred thirty-one million, four hundred fourteen thousand, one hundred thirty-one".
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