Base | Representation |
---|---|
bin | 10111100100111000… |
… | …010101110110101101 |
3 | 2102100020021122202001 |
4 | 113210320111312231 |
5 | 403321042430214 |
6 | 15343544132301 |
7 | 1554216226414 |
oct | 274470256655 |
9 | 72306248661 |
10 | 25314811309 |
11 | a810607467 |
12 | 4aa5a67091 |
13 | 250581bab8 |
14 | 13220d447b |
15 | 9d2659c74 |
hex | 5e4e15dad |
25314811309 has 2 divisors, whose sum is σ = 25314811310. Its totient is φ = 25314811308.
The previous prime is 25314811303. The next prime is 25314811337. The reversal of 25314811309 is 90311841352.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19903002084 + 5411809225 = 141078^2 + 73565^2 .
It is a cyclic number.
It is not a de Polignac number, because 25314811309 - 213 = 25314803117 is a prime.
It is a super-2 number, since 2×253148113092 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25314811303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12657405654 + 12657405655.
It is an arithmetic number, because the mean of its divisors is an integer number (12657405655).
Almost surely, 225314811309 is an apocalyptic number.
It is an amenable number.
25314811309 is a deficient number, since it is larger than the sum of its proper divisors (1).
25314811309 is an equidigital number, since it uses as much as digits as its factorization.
25314811309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 25314811309 in words is "twenty-five billion, three hundred fourteen million, eight hundred eleven thousand, three hundred nine".
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