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25314811309 is a prime number
BaseRepresentation
bin10111100100111000…
…010101110110101101
32102100020021122202001
4113210320111312231
5403321042430214
615343544132301
71554216226414
oct274470256655
972306248661
1025314811309
11a810607467
124aa5a67091
13250581bab8
1413220d447b
159d2659c74
hex5e4e15dad

25314811309 has 2 divisors, whose sum is σ = 25314811310. Its totient is φ = 25314811308.

The previous prime is 25314811303. The next prime is 25314811337. The reversal of 25314811309 is 90311841352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19903002084 + 5411809225 = 141078^2 + 73565^2 .

It is a cyclic number.

It is not a de Polignac number, because 25314811309 - 213 = 25314803117 is a prime.

It is a super-2 number, since 2×253148113092 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25314811303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12657405654 + 12657405655.

It is an arithmetic number, because the mean of its divisors is an integer number (12657405655).

Almost surely, 225314811309 is an apocalyptic number.

It is an amenable number.

25314811309 is a deficient number, since it is larger than the sum of its proper divisors (1).

25314811309 is an equidigital number, since it uses as much as digits as its factorization.

25314811309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 37.

The spelling of 25314811309 in words is "twenty-five billion, three hundred fourteen million, eight hundred eleven thousand, three hundred nine".