Base | Representation |
---|---|
bin | 11110001011100… |
… | …01000100010101 |
3 | 122122101100212111 |
4 | 33011301010111 |
5 | 1004302414231 |
6 | 41042151021 |
7 | 6162623533 |
oct | 1705610425 |
9 | 578340774 |
10 | 253169941 |
11 | 11a9a9362 |
12 | 70952471 |
13 | 405b24cb |
14 | 258a3153 |
15 | 1735d4b1 |
hex | f171115 |
253169941 has 2 divisors, whose sum is σ = 253169942. Its totient is φ = 253169940.
The previous prime is 253169921. The next prime is 253169951. The reversal of 253169941 is 149961352.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 246647025 + 6522916 = 15705^2 + 2554^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-253169941 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 253169894 and 253169903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (253169921) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126584970 + 126584971.
It is an arithmetic number, because the mean of its divisors is an integer number (126584971).
Almost surely, 2253169941 is an apocalyptic number.
It is an amenable number.
253169941 is a deficient number, since it is larger than the sum of its proper divisors (1).
253169941 is an equidigital number, since it uses as much as digits as its factorization.
253169941 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 58320, while the sum is 40.
The square root of 253169941 is about 15911.3148733849. The cubic root of 253169941 is about 632.6119335090.
The spelling of 253169941 in words is "two hundred fifty-three million, one hundred sixty-nine thousand, nine hundred forty-one".
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