2531999040 has 224 divisors, whose sum is σ = 8695724544. Its totient is φ = 621772800.

The previous prime is 2531999027. The next prime is 2531999053. The reversal of 2531999040 is 409991352.

2531999040 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (2531999027) and next prime (2531999053).

It is a super-2 number, since 2×2531999040² = 12822038277121843200, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2531998983 and 2531999001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 765390 + ... + 768690.

Almost surely, 2^2531999040 is an apocalyptic number.

2531999040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2531999040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4347862272).

2531999040 is an abundant number, since it is smaller than the sum of its proper divisors (6163725504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2531999040 is a wasteful number, since it uses less digits than its factorization.

2531999040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3385 (or 3375 counting only the distinct ones).

The product of its (nonzero) digits is 87480, while the sum is 42.

The square root of 2531999040 is about 50318.9729624920. The cubic root of 2531999040 is about 1362.9748606018.

The spelling of 2531999040 in words is "two billion, five hundred thirty-one million, nine hundred ninety-nine thousand, forty".