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25320555012293 is a prime number
BaseRepresentation
bin1011100000111011001101…
…01011111110000011000101
310022122121210000101110210122
411300131212223332003011
511304322444040343133
6125504034041031325
75222230646312102
oct560354653760305
9108577700343718
1025320555012293
118082429220862
122a0b362785545
131118944858268
14637742a23aa9
152dd9a45b5498
hex170766afe0c5

25320555012293 has 2 divisors, whose sum is σ = 25320555012294. Its totient is φ = 25320555012292.

The previous prime is 25320555012287. The next prime is 25320555012331. The reversal of 25320555012293 is 39221055502352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24727775126209 + 592779886084 = 4972703^2 + 769922^2 .

It is a cyclic number.

It is not a de Polignac number, because 25320555012293 - 232 = 25316260044997 is a prime.

It is a super-2 number, since 2×253205550122932 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25320555012253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12660277506146 + 12660277506147.

It is an arithmetic number, because the mean of its divisors is an integer number (12660277506147).

Almost surely, 225320555012293 is an apocalyptic number.

It is an amenable number.

25320555012293 is a deficient number, since it is larger than the sum of its proper divisors (1).

25320555012293 is an equidigital number, since it uses as much as digits as its factorization.

25320555012293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810000, while the sum is 44.

The spelling of 25320555012293 in words is "twenty-five trillion, three hundred twenty billion, five hundred fifty-five million, twelve thousand, two hundred ninety-three".