Base | Representation |
---|---|
bin | 111001100100110110111000… |
… | …100111000101000011110001 |
3 | 1020012120201220121111210001002 |
4 | 321210312320213011003301 |
5 | 231142240044413403403 |
6 | 2254320202135451345 |
7 | 104223435302212205 |
oct | 7144667047050361 |
9 | 1205521817453032 |
10 | 253221484122353 |
11 | 737586a035342a |
12 | 2449802a826b55 |
13 | ab3a8b682bb46 |
14 | 4675db165ab05 |
15 | 1e41d12a93188 |
hex | e64db89c50f1 |
253221484122353 has 2 divisors, whose sum is σ = 253221484122354. Its totient is φ = 253221484122352.
The previous prime is 253221484122323. The next prime is 253221484122401. The reversal of 253221484122353 is 353221484122352.
253221484122353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 239893384434064 + 13328099688289 = 15488492^2 + 3650767^2 .
It is a cyclic number.
It is not a de Polignac number, because 253221484122353 - 222 = 253221479928049 is a prime.
It is a super-3 number, since 3×2532214841223533 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 253221484122298 and 253221484122307.
It is not a weakly prime, because it can be changed into another prime (253221484122323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126610742061176 + 126610742061177.
It is an arithmetic number, because the mean of its divisors is an integer number (126610742061177).
Almost surely, 2253221484122353 is an apocalyptic number.
It is an amenable number.
253221484122353 is a deficient number, since it is larger than the sum of its proper divisors (1).
253221484122353 is an equidigital number, since it uses as much as digits as its factorization.
253221484122353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2764800, while the sum is 47.
Subtracting 253221484122353 from its reverse (353221484122352), we obtain a palindrome (99999999999999).
The spelling of 253221484122353 in words is "two hundred fifty-three trillion, two hundred twenty-one billion, four hundred eighty-four million, one hundred twenty-two thousand, three hundred fifty-three".
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