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253229393191361 is a prime number
BaseRepresentation
bin111001100100111110010000…
…000001110010000111000001
31020012121111022210211010001212
4321210332100001302013001
5231142402244124110421
62254323551030335505
7104224135300201346
oct7144762001620701
91205544283733055
10253229393191361
1173760a89863aa4
12244996774ba595
13ab3b577285332
144676521c147cd
151e421270cae5b
hexe64f900721c1

253229393191361 has 2 divisors, whose sum is σ = 253229393191362. Its totient is φ = 253229393191360.

The previous prime is 253229393191301. The next prime is 253229393191363. The reversal of 253229393191361 is 163191393922352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 247383950661136 + 5845442530225 = 15728444^2 + 2417735^2 .

It is a cyclic number.

It is not a de Polignac number, because 253229393191361 - 210 = 253229393190337 is a prime.

Together with 253229393191363, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 253229393191361.

It is not a weakly prime, because it can be changed into another prime (253229393191363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126614696595680 + 126614696595681.

It is an arithmetic number, because the mean of its divisors is an integer number (126614696595681).

Almost surely, 2253229393191361 is an apocalyptic number.

It is an amenable number.

253229393191361 is a deficient number, since it is larger than the sum of its proper divisors (1).

253229393191361 is an equidigital number, since it uses as much as digits as its factorization.

253229393191361 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14171760, while the sum is 59.

The spelling of 253229393191361 in words is "two hundred fifty-three trillion, two hundred twenty-nine billion, three hundred ninety-three million, one hundred ninety-one thousand, three hundred sixty-one".