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253314400253477 is a prime number
BaseRepresentation
bin111001100110001101011010…
…110101111111011000100101
31020012220121202002121022000212
4321212031122311333120211
5231200300342431102402
62254431010130545205
7104233234661252603
oct7146153265773045
91205817662538025
10253314400253477
1173794041060a42
12244b2040138205
13ab465a384c2a4
14467a6a796c873
151e4444ee48952
hexe6635ad7f625

253314400253477 has 2 divisors, whose sum is σ = 253314400253478. Its totient is φ = 253314400253476.

The previous prime is 253314400253443. The next prime is 253314400253501. The reversal of 253314400253477 is 774352004413352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 248878831499236 + 4435568754241 = 15775894^2 + 2106079^2 .

It is a cyclic number.

It is not a de Polignac number, because 253314400253477 - 218 = 253314399991333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253314400243477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126657200126738 + 126657200126739.

It is an arithmetic number, because the mean of its divisors is an integer number (126657200126739).

Almost surely, 2253314400253477 is an apocalyptic number.

It is an amenable number.

253314400253477 is a deficient number, since it is larger than the sum of its proper divisors (1).

253314400253477 is an equidigital number, since it uses as much as digits as its factorization.

253314400253477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8467200, while the sum is 50.

The spelling of 253314400253477 in words is "two hundred fifty-three trillion, three hundred fourteen billion, four hundred million, two hundred fifty-three thousand, four hundred seventy-seven".