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253314497 is a prime number
BaseRepresentation
bin11110001100101…
…00010111000001
3122122122201011102
433012110113001
51004322030442
641045224145
76164065142
oct1706242701
9578581142
10253314497
1111aa97a27
1270a02055
1340633247
14258ddac9
151738b232
hexf1945c1

253314497 has 2 divisors, whose sum is σ = 253314498. Its totient is φ = 253314496.

The previous prime is 253314491. The next prime is 253314541. The reversal of 253314497 is 794413352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 180741136 + 72573361 = 13444^2 + 8519^2 .

It is a cyclic number.

It is not a de Polignac number, because 253314497 - 218 = 253052353 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 253314497.

It is not a weakly prime, because it can be changed into another prime (253314491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126657248 + 126657249.

It is an arithmetic number, because the mean of its divisors is an integer number (126657249).

Almost surely, 2253314497 is an apocalyptic number.

It is an amenable number.

253314497 is a deficient number, since it is larger than the sum of its proper divisors (1).

253314497 is an equidigital number, since it uses as much as digits as its factorization.

253314497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90720, while the sum is 38.

The square root of 253314497 is about 15915.8567786971. The cubic root of 253314497 is about 632.7323143762.

The spelling of 253314497 in words is "two hundred fifty-three million, three hundred fourteen thousand, four hundred ninety-seven".