Base | Representation |
---|---|
bin | 111001100110010011001100… |
… | …100111111101010111100101 |
3 | 1020012221012202110022122110121 |
4 | 321212103030213331113211 |
5 | 231200401044130121000 |
6 | 2254433513505521541 |
7 | 104233544502414346 |
oct | 7146231447752745 |
9 | 1205835673278417 |
10 | 253320604145125 |
11 | 73796734a92620 |
12 | 244b32919432b1 |
13 | ab47051c357aa |
14 | 467aad58940cd |
15 | 1e446b4908b1a |
hex | e664cc9fd5e5 |
253320604145125 has 32 divisors (see below), whose sum is σ = 345004286515200. Its totient is φ = 184169171704000.
The previous prime is 253320604145101. The next prime is 253320604145173. The reversal of 253320604145125 is 521541406023352.
It is not a de Polignac number, because 253320604145125 - 215 = 253320604112357 is a prime.
It is a super-2 number, since 2×2533206041451252 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28037410 + ... + 35954659.
It is an arithmetic number, because the mean of its divisors is an integer number (10781383953600).
Almost surely, 2253320604145125 is an apocalyptic number.
253320604145125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
253320604145125 is a deficient number, since it is larger than the sum of its proper divisors (91683682370075).
253320604145125 is a wasteful number, since it uses less digits than its factorization.
253320604145125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63994974 (or 63994964 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 253320604145125 in words is "two hundred fifty-three trillion, three hundred twenty billion, six hundred four million, one hundred forty-five thousand, one hundred twenty-five".
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