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253357443761 is a prime number
BaseRepresentation
bin1110101111110101000…
…1111100101010110001
3220012221220201200010012
43223331101330222301
513122334001200021
6312220225144305
724206301511352
oct3537521745261
9805856650105
10253357443761
11984a2743464
1241128a8b095
131ab788347c6
14c3966a1d29
1568cc96735b
hex3afd47cab1

253357443761 has 2 divisors, whose sum is σ = 253357443762. Its totient is φ = 253357443760.

The previous prime is 253357443701. The next prime is 253357443763. The reversal of 253357443761 is 167344753352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 177878123536 + 75479320225 = 421756^2 + 274735^2 .

It is a cyclic number.

It is not a de Polignac number, because 253357443761 - 226 = 253290334897 is a prime.

Together with 253357443763, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (253357443763) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126678721880 + 126678721881.

It is an arithmetic number, because the mean of its divisors is an integer number (126678721881).

Almost surely, 2253357443761 is an apocalyptic number.

It is an amenable number.

253357443761 is a deficient number, since it is larger than the sum of its proper divisors (1).

253357443761 is an equidigital number, since it uses as much as digits as its factorization.

253357443761 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6350400, while the sum is 50.

The spelling of 253357443761 in words is "two hundred fifty-three billion, three hundred fifty-seven million, four hundred forty-three thousand, seven hundred sixty-one".