Base | Representation |
---|---|
bin | 1001011100001010… |
… | …1001110100011101 |
3 | 20112121021100020012 |
4 | 2113002221310131 |
5 | 20142204231242 |
6 | 1055241333005 |
7 | 116540054012 |
oct | 22702516435 |
9 | 6477240205 |
10 | 2534055197 |
11 | 10904541a3 |
12 | 5a8797165 |
13 | 314cc415b |
14 | 1a0797709 |
15 | ec706282 |
hex | 970a9d1d |
2534055197 has 2 divisors, whose sum is σ = 2534055198. Its totient is φ = 2534055196.
The previous prime is 2534055193. The next prime is 2534055269. The reversal of 2534055197 is 7915504352.
2534055197 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2176315801 + 357739396 = 46651^2 + 18914^2 .
It is a cyclic number.
It is not a de Polignac number, because 2534055197 - 22 = 2534055193 is a prime.
It is a super-3 number, since 3×25340551973 (a number of 29 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2534055193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1267027598 + 1267027599.
It is an arithmetic number, because the mean of its divisors is an integer number (1267027599).
Almost surely, 22534055197 is an apocalyptic number.
It is an amenable number.
2534055197 is a deficient number, since it is larger than the sum of its proper divisors (1).
2534055197 is an equidigital number, since it uses as much as digits as its factorization.
2534055197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 189000, while the sum is 41.
The square root of 2534055197 is about 50339.4000460872. The cubic root of 2534055197 is about 1363.3437038219.
The spelling of 2534055197 in words is "two billion, five hundred thirty-four million, fifty-five thousand, one hundred ninety-seven".
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