Base | Representation |
---|---|
bin | 100100111000000100101… |
… | …000000010100111001111 |
3 | 22222020222100212020101010 |
4 | 210320010220002213033 |
5 | 313004323211404332 |
6 | 5220053035420303 |
7 | 351040365142353 |
oct | 44700450024717 |
9 | 8866870766333 |
10 | 2534108309967 |
11 | 897789093403 |
12 | 34b1638b4693 |
13 | 154c71c5b980 |
14 | 8a9199c7463 |
15 | 45db82569cc |
hex | 24e04a029cf |
2534108309967 has 32 divisors (see below), whose sum is σ = 3711892879296. Its totient is φ = 1528163020800.
The previous prime is 2534108309939. The next prime is 2534108309969. The reversal of 2534108309967 is 7699038014352.
It is not a de Polignac number, because 2534108309967 - 27 = 2534108309839 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2534108309969) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 950367 + ... + 2443647.
It is an arithmetic number, because the mean of its divisors is an integer number (115996652478).
It is a 1-persistent number, because it is pandigital, but 2⋅2534108309967 = 5068216619934 is not.
Almost surely, 22534108309967 is an apocalyptic number.
2534108309967 is a deficient number, since it is larger than the sum of its proper divisors (1177784569329).
2534108309967 is a wasteful number, since it uses less digits than its factorization.
2534108309967 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1494171.
The product of its (nonzero) digits is 9797760, while the sum is 57.
The spelling of 2534108309967 in words is "two trillion, five hundred thirty-four billion, one hundred eight million, three hundred nine thousand, nine hundred sixty-seven".
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