Base | Representation |
---|---|
bin | 100100111000010010101… |
… | …100011110110111101111 |
3 | 22222021120211000120201021 |
4 | 210320102230132313233 |
5 | 313010314123332221 |
6 | 5220132310555011 |
7 | 351046262404246 |
oct | 44702254366757 |
9 | 8867524016637 |
10 | 2534344355311 |
11 | 89789a3557aa |
12 | 34b20a968a67 |
13 | 154cabb26782 |
14 | 8a93d0ad95d |
15 | 45dcdd31041 |
hex | 24e12b1edef |
2534344355311 has 2 divisors, whose sum is σ = 2534344355312. Its totient is φ = 2534344355310.
The previous prime is 2534344355293. The next prime is 2534344355339. The reversal of 2534344355311 is 1135534434352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2534344355311 - 27 = 2534344355183 is a prime.
It is a super-2 number, since 2×25343443553112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2534344355381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1267172177655 + 1267172177656.
It is an arithmetic number, because the mean of its divisors is an integer number (1267172177656).
Almost surely, 22534344355311 is an apocalyptic number.
2534344355311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2534344355311 is an equidigital number, since it uses as much as digits as its factorization.
2534344355311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296000, while the sum is 43.
Adding to 2534344355311 its reverse (1135534434352), we get a palindrome (3669878789663).
The spelling of 2534344355311 in words is "two trillion, five hundred thirty-four billion, three hundred forty-four million, three hundred fifty-five thousand, three hundred eleven".
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