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253441531309 is a prime number
BaseRepresentation
bin1110110000001001001…
…0101101110110101101
3220020011202221202112211
43230002102231312231
513123022013000214
6312232431330421
724211342320511
oct3540222556655
9806152852484
10253441531309
11985361566aa
1241151080a11
131ab90096555
14c3a3910141
1568d50270c4
hex3b024addad

253441531309 has 2 divisors, whose sum is σ = 253441531310. Its totient is φ = 253441531308.

The previous prime is 253441531289. The next prime is 253441531319. The reversal of 253441531309 is 903135144352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 153411655684 + 100029875625 = 391678^2 + 316275^2 .

It is a cyclic number.

It is not a de Polignac number, because 253441531309 - 213 = 253441523117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253441531319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126720765654 + 126720765655.

It is an arithmetic number, because the mean of its divisors is an integer number (126720765655).

Almost surely, 2253441531309 is an apocalyptic number.

It is an amenable number.

253441531309 is a deficient number, since it is larger than the sum of its proper divisors (1).

253441531309 is an equidigital number, since it uses as much as digits as its factorization.

253441531309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 40.

The spelling of 253441531309 in words is "two hundred fifty-three billion, four hundred forty-one million, five hundred thirty-one thousand, three hundred nine".