Base | Representation |
---|---|
bin | 100100111000110011110… |
… | …011111000101111010111 |
3 | 22222100000112110102200012 |
4 | 210320303303320233113 |
5 | 313012433341210112 |
6 | 5220303355110435 |
7 | 351066120004445 |
oct | 44706363705727 |
9 | 8870015412605 |
10 | 2534899944407 |
11 | 898054a30046 |
12 | 34b344a4241b |
13 | 155069c72c0c |
14 | 8a992bb5b95 |
15 | 45e129ca022 |
hex | 24e33cf8bd7 |
2534899944407 has 2 divisors, whose sum is σ = 2534899944408. Its totient is φ = 2534899944406.
The previous prime is 2534899944377. The next prime is 2534899944413. The reversal of 2534899944407 is 7044499984352.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2534899944407 - 28 = 2534899944151 is a prime.
It is a super-2 number, since 2×25348999444072 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2534899944487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1267449972203 + 1267449972204.
It is an arithmetic number, because the mean of its divisors is an integer number (1267449972204).
Almost surely, 22534899944407 is an apocalyptic number.
2534899944407 is a deficient number, since it is larger than the sum of its proper divisors (1).
2534899944407 is an equidigital number, since it uses as much as digits as its factorization.
2534899944407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 313528320, while the sum is 68.
The spelling of 2534899944407 in words is "two trillion, five hundred thirty-four billion, eight hundred ninety-nine million, nine hundred forty-four thousand, four hundred seven".
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