Base | Representation |
---|---|
bin | 100100111001000110100… |
… | …010010101011001100011 |
3 | 22222100211102121201021021 |
4 | 210321012202111121203 |
5 | 313014104303012212 |
6 | 5220354500510311 |
7 | 351106653244144 |
oct | 44710642253143 |
9 | 8870742551237 |
10 | 2535214110307 |
11 | 8981a62aa58a |
12 | 34b4120ab397 |
13 | 1550ba0907b8 |
14 | 8a9c27d5acb |
15 | 45e30386307 |
hex | 24e46895663 |
2535214110307 has 2 divisors, whose sum is σ = 2535214110308. Its totient is φ = 2535214110306.
The previous prime is 2535214110259. The next prime is 2535214110371. The reversal of 2535214110307 is 7030114125352.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2535214110307 is a prime.
It is not a weakly prime, because it can be changed into another prime (2535214110007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1267607055153 + 1267607055154.
It is an arithmetic number, because the mean of its divisors is an integer number (1267607055154).
Almost surely, 22535214110307 is an apocalyptic number.
2535214110307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2535214110307 is an equidigital number, since it uses as much as digits as its factorization.
2535214110307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 34.
Adding to 2535214110307 its reverse (7030114125352), we get a palindrome (9565328235659).
The spelling of 2535214110307 in words is "two trillion, five hundred thirty-five billion, two hundred fourteen million, one hundred ten thousand, three hundred seven".
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