Base | Representation |
---|---|
bin | 111001101001010001111100… |
… | …000000011100100101000100 |
3 | 1020020122210101201202002112101 |
4 | 321221101330000130211010 |
5 | 231212230014432241012 |
6 | 2255111544315001444 |
7 | 104254415000663146 |
oct | 7151217400344504 |
9 | 1206583351662471 |
10 | 253525410040132 |
11 | 7386558263487a |
12 | 24526b0aa39284 |
13 | ab60460b11509 |
14 | 46869a3d4ac96 |
15 | 1e49b9ec41d57 |
hex | e6947c01c944 |
253525410040132 has 48 divisors (see below), whose sum is σ = 452459250758592. Its totient is φ = 124255783084160.
The previous prime is 253525410040117. The next prime is 253525410040139. The reversal of 253525410040132 is 231040014525352.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 253525410040091 and 253525410040100.
It is not an unprimeable number, because it can be changed into a prime (253525410040139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5564992698 + ... + 5565038254.
It is an arithmetic number, because the mean of its divisors is an integer number (9426234390804).
Almost surely, 2253525410040132 is an apocalyptic number.
It is an amenable number.
253525410040132 is a deficient number, since it is larger than the sum of its proper divisors (198933840718460).
253525410040132 is a wasteful number, since it uses less digits than its factorization.
253525410040132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69348 (or 69346 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 253525410040132 its reverse (231040014525352), we get a palindrome (484565424565484).
The spelling of 253525410040132 in words is "two hundred fifty-three trillion, five hundred twenty-five billion, four hundred ten million, forty thousand, one hundred thirty-two".
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