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2540127423173 is a prime number
BaseRepresentation
bin100100111101101011011…
…001001000101011000101
322222211111211212212102212
4210331223121020223011
5313104140110020143
65222530214113205
7351342503564354
oct44755331105305
98884454785385
102540127423173
1189a29778922a
1235036364b805
131556c0c8a312
148ad2b16d99b
154611b8b7918
hex24f6b648ac5

2540127423173 has 2 divisors, whose sum is σ = 2540127423174. Its totient is φ = 2540127423172.

The previous prime is 2540127423103. The next prime is 2540127423217. The reversal of 2540127423173 is 3713247210452.

2540127423173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2252094487204 + 288032935969 = 1500698^2 + 536687^2 .

It is a cyclic number.

It is not a de Polignac number, because 2540127423173 - 216 = 2540127357637 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2540127423173.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2540127423103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270063711586 + 1270063711587.

It is an arithmetic number, because the mean of its divisors is an integer number (1270063711587).

Almost surely, 22540127423173 is an apocalyptic number.

It is an amenable number.

2540127423173 is a deficient number, since it is larger than the sum of its proper divisors (1).

2540127423173 is an equidigital number, since it uses as much as digits as its factorization.

2540127423173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 282240, while the sum is 41.

The spelling of 2540127423173 in words is "two trillion, five hundred forty billion, one hundred twenty-seven million, four hundred twenty-three thousand, one hundred seventy-three".