Base | Representation |
---|---|
bin | 1110110010010010001… |
… | …0001001000000001101 |
3 | 220021122210220210110111 |
4 | 3230210202021000031 |
5 | 13130211044000023 |
6 | 312405432240021 |
7 | 24231516242416 |
oct | 3544442110015 |
9 | 807583823414 |
10 | 254016000013 |
11 | 98800456526 |
12 | 41291540011 |
13 | 1ac520c3169 |
14 | c419d2c80d |
15 | 691a6a000d |
hex | 3b2488900d |
254016000013 has 2 divisors, whose sum is σ = 254016000014. Its totient is φ = 254016000012.
The previous prime is 254015999987. The next prime is 254016000031. The reversal of 254016000013 is 310000610452.
Together with next prime (254016000031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 242538520324 + 11477479689 = 492482^2 + 107133^2 .
It is a cyclic number.
It is not a de Polignac number, because 254016000013 - 217 = 254015868941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254016000053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127008000006 + 127008000007.
It is an arithmetic number, because the mean of its divisors is an integer number (127008000007).
Almost surely, 2254016000013 is an apocalyptic number.
It is an amenable number.
254016000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
254016000013 is an equidigital number, since it uses as much as digits as its factorization.
254016000013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 254016000013 its reverse (310000610452), we get a palindrome (564016610465).
The spelling of 254016000013 in words is "two hundred fifty-four billion, sixteen million, thirteen", and thus it is an aban number.
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