Base | Representation |
---|---|
bin | 1110110010010011000… |
… | …1110011100010101101 |
3 | 220021200002122102101101 |
4 | 3230210301303202231 |
5 | 13130213121401123 |
6 | 312410100243101 |
7 | 24231566164423 |
oct | 3544461634255 |
9 | 807602572341 |
10 | 254020106413 |
11 | 98802800747 |
12 | 412929a0491 |
13 | 1ac52c00298 |
14 | c41a6bb113 |
15 | 691ac11aad |
hex | 3b24c738ad |
254020106413 has 2 divisors, whose sum is σ = 254020106414. Its totient is φ = 254020106412.
The previous prime is 254020106401. The next prime is 254020106437. The reversal of 254020106413 is 314601020452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 253997856324 + 22250089 = 503982^2 + 4717^2 .
It is a cyclic number.
It is not a de Polignac number, because 254020106413 - 213 = 254020098221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254020104413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127010053206 + 127010053207.
It is an arithmetic number, because the mean of its divisors is an integer number (127010053207).
Almost surely, 2254020106413 is an apocalyptic number.
It is an amenable number.
254020106413 is a deficient number, since it is larger than the sum of its proper divisors (1).
254020106413 is an equidigital number, since it uses as much as digits as its factorization.
254020106413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 254020106413 its reverse (314601020452), we get a palindrome (568621126865).
The spelling of 254020106413 in words is "two hundred fifty-four billion, twenty million, one hundred six thousand, four hundred thirteen".
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