Base | Representation |
---|---|
bin | 100100111101110000111… |
… | …101000000110111000111 |
3 | 22222211202100102112222221 |
4 | 210331300331000313013 |
5 | 313104333000330224 |
6 | 5222543345433211 |
7 | 351345015545512 |
oct | 44756075006707 |
9 | 8884670375887 |
10 | 2540220714439 |
11 | 89a335408351 |
12 | 35038a93b807 |
13 | 1557073c2355 |
14 | 8ad396d5d79 |
15 | 46124b946e4 |
hex | 24f70f40dc7 |
2540220714439 has 2 divisors, whose sum is σ = 2540220714440. Its totient is φ = 2540220714438.
The previous prime is 2540220714379. The next prime is 2540220714457. The reversal of 2540220714439 is 9344170220452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2540220714439 - 211 = 2540220712391 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2540220714395 and 2540220714404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2540220717439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270110357219 + 1270110357220.
It is an arithmetic number, because the mean of its divisors is an integer number (1270110357220).
Almost surely, 22540220714439 is an apocalyptic number.
2540220714439 is a deficient number, since it is larger than the sum of its proper divisors (1).
2540220714439 is an equidigital number, since it uses as much as digits as its factorization.
2540220714439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 43.
The spelling of 2540220714439 in words is "two trillion, five hundred forty billion, two hundred twenty million, seven hundred fourteen thousand, four hundred thirty-nine".
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