Base | Representation |
---|---|
bin | 1001011101101001… |
… | …1100010000001001 |
3 | 20120001000011020212 |
4 | 2113122130100021 |
5 | 20200303303311 |
6 | 1100023130505 |
7 | 116644055306 |
oct | 22732342011 |
9 | 6501004225 |
10 | 2540291081 |
11 | 1093a23319 |
12 | 5aa8a3a35 |
13 | 316398623 |
14 | 1a153c0ad |
15 | ed038c8b |
hex | 9769c409 |
2540291081 has 2 divisors, whose sum is σ = 2540291082. Its totient is φ = 2540291080.
The previous prime is 2540291077. The next prime is 2540291093. The reversal of 2540291081 is 1801920452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2421132025 + 119159056 = 49205^2 + 10916^2 .
It is a cyclic number.
It is not a de Polignac number, because 2540291081 - 22 = 2540291077 is a prime.
It is a super-2 number, since 2×25402910812 = 12906157552416297122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2540291071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270145540 + 1270145541.
It is an arithmetic number, because the mean of its divisors is an integer number (1270145541).
Almost surely, 22540291081 is an apocalyptic number.
It is an amenable number.
2540291081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2540291081 is an equidigital number, since it uses as much as digits as its factorization.
2540291081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 32.
The square root of 2540291081 is about 50401.3003899701. The cubic root of 2540291081 is about 1364.4611076580.
The spelling of 2540291081 in words is "two billion, five hundred forty million, two hundred ninety-one thousand, eighty-one".
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