25403319413 has 2 divisors, whose sum is σ = 25403319414. Its totient is φ = 25403319412.

The previous prime is 25403319377. The next prime is 25403319433. The reversal of 25403319413 is 31491330452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21089719729 + 4313599684 = 145223^2 + 65678^2 .

It is a cyclic number.

It is not a de Polignac number, because 25403319413 - 2¹² = 25403315317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25403319433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12701659706 + 12701659707.

It is an arithmetic number, because the mean of its divisors is an integer number (12701659707).

Almost surely, 2^25403319413 is an apocalyptic number.

It is an amenable number.

25403319413 is a deficient number, since it is larger than the sum of its proper divisors (1).

25403319413 is an equidigital number, since it uses as much as digits as its factorization.

25403319413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 35.

Adding to 25403319413 its reverse (31491330452), we get a palindrome (56894649865).

The spelling of 25403319413 in words is "twenty-five billion, four hundred three million, three hundred nineteen thousand, four hundred thirteen".