Base | Representation |
---|---|
bin | 10111101010010001… |
… | …101001011010101001 |
3 | 2102120112121112120101 |
4 | 113222101221122221 |
5 | 404012231043423 |
6 | 15400540225401 |
7 | 1556365515511 |
oct | 275221513251 |
9 | 72515545511 |
10 | 25405331113 |
11 | a857713318 |
12 | 4b1023b261 |
13 | 251b4c3506 |
14 | 1330138841 |
15 | 9da58a7ad |
hex | 5ea4696a9 |
25405331113 has 2 divisors, whose sum is σ = 25405331114. Its totient is φ = 25405331112.
The previous prime is 25405331093. The next prime is 25405331123. The reversal of 25405331113 is 31113350452.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17353319824 + 8052011289 = 131732^2 + 89733^2 .
It is a cyclic number.
It is not a de Polignac number, because 25405331113 - 225 = 25371776681 is a prime.
It is a super-2 number, since 2×254053311132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (25405331123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12702665556 + 12702665557.
It is an arithmetic number, because the mean of its divisors is an integer number (12702665557).
Almost surely, 225405331113 is an apocalyptic number.
It is an amenable number.
25405331113 is a deficient number, since it is larger than the sum of its proper divisors (1).
25405331113 is an equidigital number, since it uses as much as digits as its factorization.
25405331113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 25405331113 its reverse (31113350452), we get a palindrome (56518681565).
The spelling of 25405331113 in words is "twenty-five billion, four hundred five million, three hundred thirty-one thousand, one hundred thirteen".
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