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25405331113 is a prime number
BaseRepresentation
bin10111101010010001…
…101001011010101001
32102120112121112120101
4113222101221122221
5404012231043423
615400540225401
71556365515511
oct275221513251
972515545511
1025405331113
11a857713318
124b1023b261
13251b4c3506
141330138841
159da58a7ad
hex5ea4696a9

25405331113 has 2 divisors, whose sum is σ = 25405331114. Its totient is φ = 25405331112.

The previous prime is 25405331093. The next prime is 25405331123. The reversal of 25405331113 is 31113350452.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17353319824 + 8052011289 = 131732^2 + 89733^2 .

It is a cyclic number.

It is not a de Polignac number, because 25405331113 - 225 = 25371776681 is a prime.

It is a super-2 number, since 2×254053311132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (25405331123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12702665556 + 12702665557.

It is an arithmetic number, because the mean of its divisors is an integer number (12702665557).

Almost surely, 225405331113 is an apocalyptic number.

It is an amenable number.

25405331113 is a deficient number, since it is larger than the sum of its proper divisors (1).

25405331113 is an equidigital number, since it uses as much as digits as its factorization.

25405331113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 25405331113 its reverse (31113350452), we get a palindrome (56518681565).

The spelling of 25405331113 in words is "twenty-five billion, four hundred five million, three hundred thirty-one thousand, one hundred thirteen".