2542131131 has 2 divisors, whose sum is σ = 2542131132. Its totient is φ = 2542131130.

The previous prime is 2542131127. The next prime is 2542131133. The reversal of 2542131131 is 1311312452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2542131131 - 2² = 2542131127 is a prime.

It is a super-2 number, since 2×2542131131² = 12924861374398678322, which contains 22 as substring.

Together with 2542131133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2542131097 and 2542131106.

It is not a weakly prime, because it can be changed into another prime (2542131133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271065565 + 1271065566.

It is an arithmetic number, because the mean of its divisors is an integer number (1271065566).

Almost surely, 2^2542131131 is an apocalyptic number.

2542131131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2542131131 is an equidigital number, since it uses as much as digits as its factorization.

2542131131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 720, while the sum is 23.

The square root of 2542131131 is about 50419.5510789218. The cubic root of 2542131131 is about 1364.7904755172.

Adding to 2542131131 its reverse (1311312452), we get a palindrome (3853443583).

The spelling of 2542131131 in words is "two billion, five hundred forty-two million, one hundred thirty-one thousand, one hundred thirty-one".