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2542131481 is a prime number
BaseRepresentation
bin1001011110000101…
…1101100100011001
320120011110122210211
42113201131210121
520201241201411
61100130411121
7116665522021
oct22741354431
96504418724
102542131481
111094a7000a
125ab430aa1
13316891216
141a189aa81
15ed29e221
hex9785d919

2542131481 has 2 divisors, whose sum is σ = 2542131482. Its totient is φ = 2542131480.

The previous prime is 2542131443. The next prime is 2542131497. The reversal of 2542131481 is 1841312452.

2542131481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1598720256 + 943411225 = 39984^2 + 30715^2 .

It is a cyclic number.

It is not a de Polignac number, because 2542131481 - 213 = 2542123289 is a prime.

It is a super-2 number, since 2×25421314812 = 12924864933382506722, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2542131401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271065740 + 1271065741.

It is an arithmetic number, because the mean of its divisors is an integer number (1271065741).

Almost surely, 22542131481 is an apocalyptic number.

It is an amenable number.

2542131481 is a deficient number, since it is larger than the sum of its proper divisors (1).

2542131481 is an equidigital number, since it uses as much as digits as its factorization.

2542131481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7680, while the sum is 31.

The square root of 2542131481 is about 50419.5545497974. The cubic root of 2542131481 is about 1364.7905381519.

The spelling of 2542131481 in words is "two billion, five hundred forty-two million, one hundred thirty-one thousand, four hundred eighty-one".