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2542131497 is a prime number
BaseRepresentation
bin1001011110000101…
…1101100100101001
320120011110122211102
42113201131210221
520201241201442
61100130411145
7116665522043
oct22741354451
96504418742
102542131497
111094a70024
125ab430ab5
13316891229
141a189aa93
15ed29e232
hex9785d929

2542131497 has 2 divisors, whose sum is σ = 2542131498. Its totient is φ = 2542131496.

The previous prime is 2542131481. The next prime is 2542131517. The reversal of 2542131497 is 7941312452.

2542131497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2539756816 + 2374681 = 50396^2 + 1541^2 .

It is a cyclic number.

It is not a de Polignac number, because 2542131497 - 24 = 2542131481 is a prime.

It is a super-2 number, since 2×25421314972 = 12924865096078922018, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2542131497.

It is not a weakly prime, because it can be changed into another prime (2542131197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271065748 + 1271065749.

It is an arithmetic number, because the mean of its divisors is an integer number (1271065749).

Almost surely, 22542131497 is an apocalyptic number.

It is an amenable number.

2542131497 is a deficient number, since it is larger than the sum of its proper divisors (1).

2542131497 is an equidigital number, since it uses as much as digits as its factorization.

2542131497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480, while the sum is 38.

The square root of 2542131497 is about 50419.5547084660. The cubic root of 2542131497 is about 1364.7905410152.

The spelling of 2542131497 in words is "two billion, five hundred forty-two million, one hundred thirty-one thousand, four hundred ninety-seven".