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2542131541 is a prime number
BaseRepresentation
bin1001011110000101…
…1101100101010101
320120011110122220001
42113201131211111
520201241202131
61100130411301
7116665522135
oct22741354525
96504418801
102542131541
111094a70064
125ab430b31
13316891261
141a189aac5
15ed29e261
hex9785d955

2542131541 has 2 divisors, whose sum is σ = 2542131542. Its totient is φ = 2542131540.

The previous prime is 2542131517. The next prime is 2542131589. The reversal of 2542131541 is 1451312452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2489511025 + 52620516 = 49895^2 + 7254^2 .

It is a cyclic number.

It is not a de Polignac number, because 2542131541 - 215 = 2542098773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2542131041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271065770 + 1271065771.

It is an arithmetic number, because the mean of its divisors is an integer number (1271065771).

Almost surely, 22542131541 is an apocalyptic number.

It is an amenable number.

2542131541 is a deficient number, since it is larger than the sum of its proper divisors (1).

2542131541 is an equidigital number, since it uses as much as digits as its factorization.

2542131541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4800, while the sum is 28.

The square root of 2542131541 is about 50419.5551448047. Note that the first 3 decimals coincide. The cubic root of 2542131541 is about 1364.7905488892.

Adding to 2542131541 its reverse (1451312452), we get a palindrome (3993443993).

The spelling of 2542131541 in words is "two billion, five hundred forty-two million, one hundred thirty-one thousand, five hundred forty-one".