Base | Representation |
---|---|
bin | 100101000000101000101… |
… | …011111101001001000001 |
3 | 100000010201011202121112002 |
4 | 211000220223331021001 |
5 | 313132141113003442 |
6 | 5224213303113345 |
7 | 351514265636222 |
oct | 45005053751101 |
9 | 10003634677462 |
10 | 2543303250497 |
11 | 8a0677421309 |
12 | 350aab142855 |
13 | 155aa8c14399 |
14 | 8b14cc65249 |
15 | 462555dd732 |
hex | 25028afd241 |
2543303250497 has 2 divisors, whose sum is σ = 2543303250498. Its totient is φ = 2543303250496.
The previous prime is 2543303250491. The next prime is 2543303250529. The reversal of 2543303250497 is 7940523033452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1883437843456 + 659865407041 = 1372384^2 + 812321^2 .
It is a cyclic number.
It is not a de Polignac number, because 2543303250497 - 224 = 2543286473281 is a prime.
It is not a weakly prime, because it can be changed into another prime (2543303250491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271651625248 + 1271651625249.
It is an arithmetic number, because the mean of its divisors is an integer number (1271651625249).
Almost surely, 22543303250497 is an apocalyptic number.
It is an amenable number.
2543303250497 is a deficient number, since it is larger than the sum of its proper divisors (1).
2543303250497 is an equidigital number, since it uses as much as digits as its factorization.
2543303250497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2721600, while the sum is 47.
The spelling of 2543303250497 in words is "two trillion, five hundred forty-three billion, three hundred three million, two hundred fifty thousand, four hundred ninety-seven".
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