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2543303250541 is a prime number
BaseRepresentation
bin100101000000101000101…
…011111101001001101101
3100000010201011202121120201
4211000220223331021231
5313132141113004131
65224213303113501
7351514265636314
oct45005053751155
910003634677521
102543303250541
118a0677421349
12350aab142891
13155aa8c14401
148b14cc6527b
15462555dd761
hex25028afd26d

2543303250541 has 2 divisors, whose sum is σ = 2543303250542. Its totient is φ = 2543303250540.

The previous prime is 2543303250529. The next prime is 2543303250611. The reversal of 2543303250541 is 1450523033452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2254051822500 + 289251428041 = 1501350^2 + 537821^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2543303250541 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2543303250541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2543303250041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271651625270 + 1271651625271.

It is an arithmetic number, because the mean of its divisors is an integer number (1271651625271).

Almost surely, 22543303250541 is an apocalyptic number.

It is an amenable number.

2543303250541 is a deficient number, since it is larger than the sum of its proper divisors (1).

2543303250541 is an equidigital number, since it uses as much as digits as its factorization.

2543303250541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 2543303250541 its reverse (1450523033452), we get a palindrome (3993826283993).

The spelling of 2543303250541 in words is "two trillion, five hundred forty-three billion, three hundred three million, two hundred fifty thousand, five hundred forty-one".