Base | Representation |
---|---|
bin | 100101000000101100001… |
… | …100110110001000001001 |
3 | 100000010212021200202202102 |
4 | 211000230030312020021 |
5 | 313132301211013134 |
6 | 5224223210443145 |
7 | 351515613014633 |
oct | 45005414661011 |
9 | 10003767622672 |
10 | 2543362204169 |
11 | 8a06a7728056 |
12 | 350b06a334b5 |
13 | 155ab81b6007 |
14 | 8b156a0da53 |
15 | 4625a88637e |
hex | 2502c336209 |
2543362204169 has 2 divisors, whose sum is σ = 2543362204170. Its totient is φ = 2543362204168.
The previous prime is 2543362204151. The next prime is 2543362204183. The reversal of 2543362204169 is 9614022633452.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2066440750144 + 476921454025 = 1437512^2 + 690595^2 .
It is a cyclic number.
It is not a de Polignac number, because 2543362204169 - 212 = 2543362200073 is a prime.
It is a super-2 number, since 2×25433622041692 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2543362204109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271681102084 + 1271681102085.
It is an arithmetic number, because the mean of its divisors is an integer number (1271681102085).
Almost surely, 22543362204169 is an apocalyptic number.
It is an amenable number.
2543362204169 is a deficient number, since it is larger than the sum of its proper divisors (1).
2543362204169 is an equidigital number, since it uses as much as digits as its factorization.
2543362204169 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1866240, while the sum is 47.
The spelling of 2543362204169 in words is "two trillion, five hundred forty-three billion, three hundred sixty-two million, two hundred four thousand, one hundred sixty-nine".
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