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254341140388477 is a prime number
BaseRepresentation
bin111001110101001001101001…
…010100110001101001111101
31020100112202221101022022210021
4321311021221110301221331
5231314111123414412402
62300534412403212141
7104400353363355112
oct7165115124615175
91210482841268707
10254341140388477
117404a5210a905a
1224639025377051
13abbc360a109cc
1446b42694d0909
151e60ee4012d37
hexe75269531a7d

254341140388477 has 2 divisors, whose sum is σ = 254341140388478. Its totient is φ = 254341140388476.

The previous prime is 254341140388463. The next prime is 254341140388481. The reversal of 254341140388477 is 774883041143452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 205768868865316 + 48572271523161 = 14344646^2 + 6969381^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-254341140388477 is a prime.

It is a super-2 number, since 2×2543411403884772 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254341140388427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127170570194238 + 127170570194239.

It is an arithmetic number, because the mean of its divisors is an integer number (127170570194239).

Almost surely, 2254341140388477 is an apocalyptic number.

It is an amenable number.

254341140388477 is a deficient number, since it is larger than the sum of its proper divisors (1).

254341140388477 is an equidigital number, since it uses as much as digits as its factorization.

254341140388477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72253440, while the sum is 61.

The spelling of 254341140388477 in words is "two hundred fifty-four trillion, three hundred forty-one billion, one hundred forty million, three hundred eighty-eight thousand, four hundred seventy-seven".