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254390105341 is a prime number
BaseRepresentation
bin1110110011101011010…
…1001111010011111101
3220022121212212022111101
43230322311033103331
513131442331332331
6312510514453101
724244011134461
oct3547265172375
9808555768441
10254390105341
1198982645389
1241376894191
131acb1769268
14c4538b24a1
15693d44b061
hex3b3ad4f4fd

254390105341 has 2 divisors, whose sum is σ = 254390105342. Its totient is φ = 254390105340.

The previous prime is 254390105327. The next prime is 254390105357. The reversal of 254390105341 is 143501093452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 208442468025 + 45947637316 = 456555^2 + 214354^2 .

It is a cyclic number.

It is not a de Polignac number, because 254390105341 - 211 = 254390103293 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 254390105341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254390105941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127195052670 + 127195052671.

It is an arithmetic number, because the mean of its divisors is an integer number (127195052671).

Almost surely, 2254390105341 is an apocalyptic number.

It is an amenable number.

254390105341 is a deficient number, since it is larger than the sum of its proper divisors (1).

254390105341 is an equidigital number, since it uses as much as digits as its factorization.

254390105341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 254390105341 its reverse (143501093452), we get a palindrome (397891198793).

The spelling of 254390105341 in words is "two hundred fifty-four billion, three hundred ninety million, one hundred five thousand, three hundred forty-one".