25440201401 has 2 divisors, whose sum is σ = 25440201402. Its totient is φ = 25440201400.

The previous prime is 25440201383. The next prime is 25440201403. The reversal of 25440201401 is 10410204452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25439931001 + 270400 = 159499^2 + 520^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-25440201401 is a prime.

Together with 25440201403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (25440201403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12720100700 + 12720100701.

It is an arithmetic number, because the mean of its divisors is an integer number (12720100701).

Almost surely, 2^25440201401 is an apocalyptic number.

It is an amenable number.

25440201401 is a deficient number, since it is larger than the sum of its proper divisors (1).

25440201401 is an equidigital number, since it uses as much as digits as its factorization.

25440201401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 23.

Adding to 25440201401 its reverse (10410204452), we get a palindrome (35850405853).

The spelling of 25440201401 in words is "twenty-five billion, four hundred forty million, two hundred one thousand, four hundred one".