25440421205443 has 2 divisors, whose sum is σ = 25440421205444. Its totient is φ = 25440421205442.

The previous prime is 25440421205411. The next prime is 25440421205477. The reversal of 25440421205443 is 34450212404452.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25440421205443 - 2⁵ = 25440421205411 is a prime.

It is a super-2 number, since 2×25440421205443² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25440421205396 and 25440421205405.

It is not a weakly prime, because it can be changed into another prime (25440421209443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12720210602721 + 12720210602722.

It is an arithmetic number, because the mean of its divisors is an integer number (12720210602722).

Almost surely, 2^{25440421205443} is an apocalyptic number.

25440421205443 is a deficient number, since it is larger than the sum of its proper divisors (1).

25440421205443 is an equidigital number, since it uses as much as digits as its factorization.

25440421205443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 614400, while the sum is 40.

Adding to 25440421205443 its reverse (34450212404452), we get a palindrome (59890633609895).

The spelling of 25440421205443 in words is "twenty-five trillion, four hundred forty billion, four hundred twenty-one million, two hundred five thousand, four hundred forty-three".