Base | Representation |
---|---|
bin | 1011100100011010011110… |
… | …10001001101010110100011 |
3 | 10100002002011200202222202122 |
4 | 11302031033101031112203 |
5 | 11313303440312033121 |
6 | 130035100153334455 |
7 | 5234003232200012 |
oct | 562151721152643 |
9 | 110062150688678 |
10 | 25440421205411 |
11 | 81192495a3883 |
12 | 2a2a63570742b |
13 | 11270380c3154 |
14 | 63d474298a79 |
15 | 2e1b6c9395ab |
hex | 17234f44d5a3 |
25440421205411 has 2 divisors, whose sum is σ = 25440421205412. Its totient is φ = 25440421205410.
The previous prime is 25440421205401. The next prime is 25440421205443. The reversal of 25440421205411 is 11450212404452.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25440421205411 - 230 = 25439347463587 is a prime.
It is a super-2 number, since 2×254404212054112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (25440421205401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12720210602705 + 12720210602706.
It is an arithmetic number, because the mean of its divisors is an integer number (12720210602706).
Almost surely, 225440421205411 is an apocalyptic number.
25440421205411 is a deficient number, since it is larger than the sum of its proper divisors (1).
25440421205411 is an equidigital number, since it uses as much as digits as its factorization.
25440421205411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51200, while the sum is 35.
Adding to 25440421205411 its reverse (11450212404452), we get a palindrome (36890633609863).
The spelling of 25440421205411 in words is "twenty-five trillion, four hundred forty billion, four hundred twenty-one million, two hundred five thousand, four hundred eleven".
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