Base | Representation |
---|---|
bin | 1110110100110000010… |
… | …0100101101001100111 |
3 | 220100101001010001011001 |
4 | 3231030010211221213 |
5 | 13133040402413141 |
6 | 312555330054131 |
7 | 24254122454206 |
oct | 3551404455147 |
9 | 810331101131 |
10 | 254679341671 |
11 | 99010937977 |
12 | 4143771a347 |
13 | 1b029668a11 |
14 | c48008323d |
15 | 6958a30a31 |
hex | 3b4c125a67 |
254679341671 has 2 divisors, whose sum is σ = 254679341672. Its totient is φ = 254679341670.
The previous prime is 254679341647. The next prime is 254679341677. The reversal of 254679341671 is 176143976452.
254679341671 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 254679341671 - 25 = 254679341639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254679341677) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127339670835 + 127339670836.
It is an arithmetic number, because the mean of its divisors is an integer number (127339670836).
Almost surely, 2254679341671 is an apocalyptic number.
254679341671 is a deficient number, since it is larger than the sum of its proper divisors (1).
254679341671 is an equidigital number, since it uses as much as digits as its factorization.
254679341671 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7620480, while the sum is 55.
The spelling of 254679341671 in words is "two hundred fifty-four billion, six hundred seventy-nine million, three hundred forty-one thousand, six hundred seventy-one".
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