Base | Representation |
---|---|
bin | 1110110100111110110… |
… | …1101100101011101111 |
3 | 220100112022002200001122 |
4 | 3231033231230223233 |
5 | 13133202023400111 |
6 | 313005351531155 |
7 | 24255464045534 |
oct | 3551755545357 |
9 | 810468080048 |
10 | 254740450031 |
11 | 99042385551 |
12 | 41454089abb |
13 | 1b039213302 |
14 | c48822cd8b |
15 | 695e0a1cdb |
hex | 3b4fb6caef |
254740450031 has 2 divisors, whose sum is σ = 254740450032. Its totient is φ = 254740450030.
The previous prime is 254740449989. The next prime is 254740450049. The reversal of 254740450031 is 130054047452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 254740450031 - 218 = 254740187887 is a prime.
It is a super-2 number, since 2×2547404500312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 254740449973 and 254740450000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254740450051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127370225015 + 127370225016.
It is an arithmetic number, because the mean of its divisors is an integer number (127370225016).
Almost surely, 2254740450031 is an apocalyptic number.
254740450031 is a deficient number, since it is larger than the sum of its proper divisors (1).
254740450031 is an equidigital number, since it uses as much as digits as its factorization.
254740450031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67200, while the sum is 35.
Adding to 254740450031 its reverse (130054047452), we get a palindrome (384794497483).
The spelling of 254740450031 in words is "two hundred fifty-four billion, seven hundred forty million, four hundred fifty thousand, thirty-one".
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