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25490766793 is a prime number
BaseRepresentation
bin10111101111010111…
…100011101111001001
32102210111101010021211
4113233113203233021
5404201114014133
615413231333121
71561453641232
oct275727435711
972714333254
1025490766793
11a8a0967418
124b349811a1
132533107a7b
14133b618089
159e2d14bcd
hex5ef5e3bc9

25490766793 has 2 divisors, whose sum is σ = 25490766794. Its totient is φ = 25490766792.

The previous prime is 25490766787. The next prime is 25490766809. The reversal of 25490766793 is 39766709452.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20594546064 + 4896220729 = 143508^2 + 69973^2 .

It is a cyclic number.

It is not a de Polignac number, because 25490766793 - 29 = 25490766281 is a prime.

It is a super-2 number, since 2×254907667932 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (25490766713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12745383396 + 12745383397.

It is an arithmetic number, because the mean of its divisors is an integer number (12745383397).

Almost surely, 225490766793 is an apocalyptic number.

It is an amenable number.

25490766793 is a deficient number, since it is larger than the sum of its proper divisors (1).

25490766793 is an equidigital number, since it uses as much as digits as its factorization.

25490766793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17146080, while the sum is 58.

The spelling of 25490766793 in words is "twenty-five billion, four hundred ninety million, seven hundred sixty-six thousand, seven hundred ninety-three".