254940137 has 2 divisors, whose sum is σ = 254940138. Its totient is φ = 254940136.

The previous prime is 254940113. The next prime is 254940139. The reversal of 254940137 is 731049452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 250398976 + 4541161 = 15824^2 + 2131^2 .

It is a cyclic number.

It is not a de Polignac number, because 254940137 - 2¹⁶ = 254874601 is a prime.

Together with 254940139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 254940097 and 254940106.

It is not a weakly prime, because it can be changed into another prime (254940139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127470068 + 127470069.

It is an arithmetic number, because the mean of its divisors is an integer number (127470069).

Almost surely, 2^254940137 is an apocalyptic number.

It is an amenable number.

254940137 is a deficient number, since it is larger than the sum of its proper divisors (1).

254940137 is an equidigital number, since it uses as much as digits as its factorization.

254940137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30240, while the sum is 35.

The square root of 254940137 is about 15966.8449294155. The cubic root of 254940137 is about 634.0829443307.

Adding to 254940137 its reverse (731049452), we get a palindrome (985989589).

The spelling of 254940137 in words is "two hundred fifty-four million, nine hundred forty thousand, one hundred thirty-seven".