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2550013050253 is a prime number
BaseRepresentation
bin100101000110111000100…
…111110011110110001101
3100000210000210102202102011
4211012320213303312031
5313234411320102003
65231243153301221
7352142462202514
oct45067047636615
910023023382364
102550013050253
118a34aa985169
12352262264811
13156608070bb6
148b5c803d67b
15464e96d246d
hex251b89f3d8d

2550013050253 has 2 divisors, whose sum is σ = 2550013050254. Its totient is φ = 2550013050252.

The previous prime is 2550013050229. The next prime is 2550013050257. The reversal of 2550013050253 is 3520503100552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1939384893924 + 610628156329 = 1392618^2 + 781427^2 .

It is a cyclic number.

It is not a de Polignac number, because 2550013050253 - 221 = 2550010953101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2550013050257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275006525126 + 1275006525127.

It is an arithmetic number, because the mean of its divisors is an integer number (1275006525127).

Almost surely, 22550013050253 is an apocalyptic number.

It is an amenable number.

2550013050253 is a deficient number, since it is larger than the sum of its proper divisors (1).

2550013050253 is an equidigital number, since it uses as much as digits as its factorization.

2550013050253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22500, while the sum is 31.

The spelling of 2550013050253 in words is "two trillion, five hundred fifty billion, thirteen million, fifty thousand, two hundred fifty-three".