Base | Representation |
---|---|
bin | 100101000110111110101… |
… | …000110111110011111111 |
3 | 100000210021211101010100222 |
4 | 211012332220313303333 |
5 | 313240113140220220 |
6 | 5231301201011555 |
7 | 352145126166236 |
oct | 45067650676377 |
9 | 10023254333328 |
10 | 2550113991935 |
11 | 8a355195a144 |
12 | 352290023bbb |
13 | 156622c541c3 |
14 | 8b5d75d7b1d |
15 | 465034c0e25 |
hex | 251bea37cff |
2550113991935 has 4 divisors (see below), whose sum is σ = 3060136790328. Its totient is φ = 2040091193544.
The previous prime is 2550113991871. The next prime is 2550113991937. The reversal of 2550113991935 is 5391993110552.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2550113991935 - 26 = 2550113991871 is a prime.
It is a super-2 number, since 2×25501139919352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2550113991937) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255011399189 + ... + 255011399198.
It is an arithmetic number, because the mean of its divisors is an integer number (765034197582).
Almost surely, 22550113991935 is an apocalyptic number.
2550113991935 is a deficient number, since it is larger than the sum of its proper divisors (510022798393).
2550113991935 is an equidigital number, since it uses as much as digits as its factorization.
2550113991935 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 510022798392.
The product of its (nonzero) digits is 1640250, while the sum is 53.
The spelling of 2550113991935 in words is "two trillion, five hundred fifty billion, one hundred thirteen million, nine hundred ninety-one thousand, nine hundred thirty-five".
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