Base | Representation |
---|---|
bin | 100101000110111110101… |
… | …000110111110010111111 |
3 | 100000210021211101010021121 |
4 | 211012332220313302333 |
5 | 313240113140214441 |
6 | 5231301201011411 |
7 | 352145126166115 |
oct | 45067650676277 |
9 | 10023254333247 |
10 | 2550113991871 |
11 | 8a355195a096 |
12 | 352290023b67 |
13 | 156622c54174 |
14 | 8b5d75d7ab5 |
15 | 465034c0dd1 |
hex | 251bea37cbf |
2550113991871 has 2 divisors, whose sum is σ = 2550113991872. Its totient is φ = 2550113991870.
The previous prime is 2550113991869. The next prime is 2550113991937. The reversal of 2550113991871 is 1781993110552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2550113991871 - 21 = 2550113991869 is a prime.
Together with 2550113991869, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2550113991071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275056995935 + 1275056995936.
It is an arithmetic number, because the mean of its divisors is an integer number (1275056995936).
Almost surely, 22550113991871 is an apocalyptic number.
2550113991871 is a deficient number, since it is larger than the sum of its proper divisors (1).
2550113991871 is an equidigital number, since it uses as much as digits as its factorization.
2550113991871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 52.
The spelling of 2550113991871 in words is "two trillion, five hundred fifty billion, one hundred thirteen million, nine hundred ninety-one thousand, eight hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •