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255012214552223 is a prime number
BaseRepresentation
bin111001111110111010101000…
…011101100011011010011111
31020102220221002200201222210112
4321332322220131203122133
5231411110003411132343
62302210554415400235
7104500011255551402
oct7176725035433237
91212827080658715
10255012214552223
1174289088a61857
12247270aa82307b
13ac3a7194bb7bb
1446d892acc1d39
151e736bd922218
hexe7eea876369f

255012214552223 has 2 divisors, whose sum is σ = 255012214552224. Its totient is φ = 255012214552222.

The previous prime is 255012214552213. The next prime is 255012214552253. The reversal of 255012214552223 is 322255412210552.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255012214552223 - 218 = 255012214290079 is a prime.

It is a super-3 number, since 3×2550122145522233 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255012214552213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127506107276111 + 127506107276112.

It is an arithmetic number, because the mean of its divisors is an integer number (127506107276112).

Almost surely, 2255012214552223 is an apocalyptic number.

255012214552223 is a deficient number, since it is larger than the sum of its proper divisors (1).

255012214552223 is an equidigital number, since it uses as much as digits as its factorization.

255012214552223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480000, while the sum is 41.

Adding to 255012214552223 its reverse (322255412210552), we get a palindrome (577267626762775).

The spelling of 255012214552223 in words is "two hundred fifty-five trillion, twelve billion, two hundred fourteen million, five hundred fifty-two thousand, two hundred twenty-three".