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25501235040581 is a prime number
BaseRepresentation
bin1011100110001011110000…
…00011100101000101000101
310100021220010220201220111012
411303011320003211011011
511320303012132244311
6130123034453052005
75241255243233006
oct563057003450505
9110256126656435
1025501235040581
118142016401293
122a3a388027005
13112c9aa3385c1
146423a2c791ad
152e352b84878b
hex1731780e5145

25501235040581 has 2 divisors, whose sum is σ = 25501235040582. Its totient is φ = 25501235040580.

The previous prime is 25501235040493. The next prime is 25501235040637. The reversal of 25501235040581 is 18504053210552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25366997072356 + 134237968225 = 5036566^2 + 366385^2 .

It is a cyclic number.

It is not a de Polignac number, because 25501235040581 - 214 = 25501235024197 is a prime.

It is a super-2 number, since 2×255012350405812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25501235040881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12750617520290 + 12750617520291.

It is an arithmetic number, because the mean of its divisors is an integer number (12750617520291).

Almost surely, 225501235040581 is an apocalyptic number.

It is an amenable number.

25501235040581 is a deficient number, since it is larger than the sum of its proper divisors (1).

25501235040581 is an equidigital number, since it uses as much as digits as its factorization.

25501235040581 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240000, while the sum is 41.

The spelling of 25501235040581 in words is "twenty-five trillion, five hundred one billion, two hundred thirty-five million, forty thousand, five hundred eighty-one".